For this case, the first thing to do is find the horizontal distance from the plane to the zoo and the library respectively.
We then have the following trigonometric relationships:
For the zoo:
[tex] tan (60) = (300 * root (3)) / d1
[/tex]
Clearing d1 we have:
[tex]d1 = (300 * root (3)) / tan (60)
d1 = 300[/tex]
For the library:
[tex] tan (30) = (300 * root (3)) / d2
[/tex]
Clearing d1 we have:
[tex] d2 = (300 * root (3)) / tan (30)
d2 = 900[/tex]
Then, the distance between zoo and library is:
[tex] d2 - d1 = 900 - 300
d2 - d1 = 600 feet[/tex]
Answer:
The distance between the zoo and the library is:
600 feet
