I NEED HELP!!!!!
What is the following sum?
5x(3 sqrt(x^2 y)+2(3 sqrt^5y)

a- 7x(^6 square root of x^2y)
b-7x^2(^6 square root of xy^2)
c-7x^2(^3 square root of xy^2)
d-7x(^3square root of x^2y)

Respuesta :

For this case we have the following function: 
 [tex]5x\sqrt[3]{x^2y} + 2 \sqrt[3]{x^5y} [/tex]
 Rewriting we have:
 [tex]5x\sqrt[3]{x^2y} + 2 \sqrt[3]{x^3x^2y} [/tex]
 Then, by properties of exponents we have:
 [tex]5x\sqrt[3]{x^2y} + 2x\sqrt[3]{x^2y} [/tex]
 Then, adding both quantities we have:
 [tex]7x\sqrt[3]{x^2y} [/tex]
 Answer:
 the following sum is:
 
d-7x(^3square root of x^2y)

Answer:

d-7x(^3square root of x^2y)

Step-by-step explanation:

The given equation is:

[tex]5x\sqrt[3]{x^2y} +2\sqrt{3}{x^5y}[/tex]

Solving this equation step by step

[tex]5x\sqrt[3]{x^2y} +2\sqrt{3}{x^5y}[/tex]

∵ x⁵ = x³ × x²

[tex]5x\sqrt[3]{x^2y} +2\sqrt[3]{(x^3\times x^2)y}[/tex]

take the x³ outside the cube root in second term

[tex]5x\sqrt[3]{x^2y} +2x\sqrt[3]{(x^2)y}\\\sqrt[3]{x^2y} (5x+2x)\\7x\sqrt[3]{x^2y}[/tex]

Thus, last option is correct.