Sit back, get a sweet tea, and chill because I'm about to teach you a thing or two on how to solve your problem!
To find a percentage, I like to use the proportion method! Basically, it's set up as: part/whole=percent/100. We can use this to find which park has the greatest percentage of green birds.
Let's start with Park P! Park P had 18 green birds (our part) and a total of 82 birds (our whole). To find the percentage, set the equation up as:
18/82=x/100
To solve, multiply the two opposite corners and then divide with the other number.
18(100) = 1800/82 = 21.95
So, Park P has a percentage of about 22%
Moving on to Park Q. Park Q has 39 green birds(part) and 88 total (whole).
39/88=x/100
39(100)=3900/44.31
Oooh, a little bit higher! Park Q has a percentage of about 44%
Next is Park R! Park R has 38 green birds (part) and 64 total (whole).
38/64=x/100
38(100)=3800/64=59.375
Wowzah! This one is about 59%!
Lastly is Park S. Park S has 22 green birds (part) and 50 total (whole).
22/50=x/100
22(100)=2200/50=44
Not too shabby with 44%.
So, which park has the greatest percentage of green birds?? Drumroll please...
*duh duh duh duh duh*
Park R has the greatest percentage with 59%!!!
Hope this helps and I hope you have a great day! Don't forget to mark brainliest! ;)
