The height in feet, h, of a model rocket t seconds after launch is given by the equation h (t) = 3 + 70t - 16t^2. The average rate of change in h(t) between t = 1 second and t = 3 second is 6. What does the average rate of change tell you about the rocket?

A. The rocket is traveling six times as fast when t = 3 than it is when t = 1.
B. The rocket is at a greater height when t = 3 than it is when t = 1.
C. The rocket is 6 feet higher above the ground when t = 3 than it is when t = 1.
D. The rocket is traveling at a constant rate of 6 feet per second between t = 1 and t = 3.

Respuesta :

average rate simply means, a constant rate something is moving about during a certain period.

now, object quite often or most always do not move at some constant speed, but the average rate gives a ballpark of how it must be moving.

so, since in this case the "slope" or average rate is a positive 6, one can say the rocket is higher at t = 3 than at t = 1.

The rocket is at a greater height when t = 3 than it is when t = 1.

Given

The height in feet, h, of a model rocket t seconds after launch is given by the equation h (t) = 3 + 70t - 16t^2.

The average rate of change in h(t) between t = 1 second and t = 3 seconds is 6.

What is differentiation?

The instantaneous rate of change in function is based on one of its variables.

On differentiation the given function;

[tex]\rm h (t) = 3 + 70t - 16t^2\\\\\dfrac{d(h)}{dt}=0+70-32t[/tex]

The average rate of change in h(t) between t = 1 second and t = 3 seconds is 6.

Therefore,

The average rate of change that tells you about the rocket is;

[tex]\rm Average \ rate = \dfrac{6}{3-1}\\\\Average rate = \dfrac{6}{2}\\\\Average \ rate =3[/tex]

Hence, the rocket is at a greater height when t = 3 than it is when t = 1.

To know more about differentiation click the link given below.

https://brainly.com/question/14866508