Respuesta :

So with this polygon, you'll gonna break it into 3 triangles: BAE, BCE, and CED. (youll need to make line BE.). After that, youre gonna find the area of each of the triangles and then add the areas all up.

Starting with triangle BAE:

Area of a triangle is [tex] A=\frac{1}{2} bh[/tex].

From point A to Line BE is 3 units. From point B to point E is 6 units. apply them into the equation.

[tex]A=\frac{1}{2} *3*6[/tex]

[tex]A= \frac{1}{2} *18[/tex]

[tex]A=9[/tex]


Now with BCE:

From point C to Line BE is 2 units. From point B to point E is 6 units. Apply them to the triangle area formula.

[tex]A= \frac{1}{2} *2*6[/tex]

[tex]A= \frac{1}{2} *12[/tex]

[tex]A=6[/tex]


Now with the last triangle:

From point C to Line ED is 3 units. From point E to point D is 5 units. Apply them to the formula.

[tex]A= \frac{1}{2} *3*5[/tex]

[tex]A= \frac{1}{2} *15[/tex]

[tex]A=7.5[/tex]


Now to add the areas:

9 + 6 + 7.5 = 22.5

22.5 un^2 is your area for this polygon.