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mathstudent55
If x2 + 6x + c = (x + d)2, then d =What value of c makes x2 + 6x + c a perfect square trinomial? c = 

Divide the x-term coefficient by 2: 6/2 = 3
Now square 3: 3^2 = 9
c = 9

If x^2 + 6x + c = (x + d)^2, then d =

x^2 + 6x + 9 = (x + 3)^2 = (x + d)^2, so d = 3
abidemiokin

The value of c = 9 and d is 3 from the resulting equation

How to write an equation in vertex form

Given the quadratic equation expressed as:

x^2 + 6x + c

We need the value of c that will make the expression a perfect polynomial.

Using the completing the square method

x^2 + 6x +  (6/2)² - (6/2)²

x² +  6x + 3² - 3²

(x² + 6x + 9) - 9

(x+3)² - 9

Hence the value of c = 9 and d is 3 from the resulting equation

Learn more on vertex form here: https://brainly.com/question/525947

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