The difference between two numbers is 28. The larger number is 8 less than twice the smaller number. Find both numbers.

Respuesta :

a-b=28 
a-8= 2b      a= 2b+8

2b+8 -b= 28
b= 20

answer 48 and 20
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Lanuel

The larger number is equal to 64 and the smaller number is equal to 36.

  • Let the smaller number be x.
  • Let the larger number be y.

To write the word problem as an algebraic equation:

In this exercise, we are required to translate the word problem into a mathematical (algebraic) expression and solve for the unknown variable (number):

Translating the word problem into an algebraic expression, we have;

The difference between two numbers is 28:

[tex]y-x=28[/tex]    ....equation 1

The larger number is 8 less than twice the smaller number:

[tex]y=2x-8[/tex]   ...equation 2

Substituting eqn 2 into eqn 1, we have:

[tex]2x-8-x=28\\\\x-8=28\\\\x=28+8[/tex]

x = 36

To find the value of y:

[tex]y=2x-8\\\\y=2(36)-8\\\\y=72-8[/tex]

y = 64

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