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perixwinkle
The second equation is perfect. We can add y to both sides to make the equation equal x.
X=5+y; let's plug that in for x in the first equation.
2(5+y)+3y=25
10+2y+3y=25
5y+10=25
Let's subtract 10 from both sides.
5y=15
Now divide both sides by 5.
Y=3
So y is 3. We can plug 3 in for y in the second equation.
X-3=5
X=8
So, X=8 and Y=3.
aosera
2x + 3y = 25
x - y = 5


x-y = 5 [make x the subject]
x= 5 +y

Now substitute,
2(5+y) + 3y =25
10 + 2y + 3y =25
10 + 5y = 25
5y = 25-10
5y=15
y=15÷5
y=3

Now to find x, substitute the value of y

x = 5 +y
x = 5 +3
x = 8

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