It'd be a lot easier to help you if you'd share the answer graphs.
Just so that you know:
f(x) = log(x + 3) + 1 can be graphed as follows:
1. Graph y = log x. This function's domain is x>0. It begins in Quadrant IV and ends in Quadrant I. It intercepts the x-axis at (1,0).
2. Now move the entire graph 1 unit to the left. This gives you the graph of y = log (x+1).
3. Now translate this entire graph up 3 units. This gives you the graph of f(x) = log(x + 3) + 1.
