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a car accelerated from 88 feet per second (fps) to 220 fps in exactly 3 seconds. Assuming the acceleration was constant, what was the cars acceleration, in feet per second per second, from 8 fps to 220 fps

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MrEquation
The acceleration would be 26.4 feet per second per second.

To find this rate, you can use the slope formula like with linear equation.

In the numerator, subtract the rates. In the denominator, subtract the times.

220 - 88 = 132
8 - 3 = 5

132 / 5 = 26.4 feet per second per second 
PortgasDAce

a=(V-V₀)/t

a=(220-88)/3=44 ft/s²

Acceleration is 44 ft/s²

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