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PLEASE HELP ME ASAPPPP
4 Fe(s) + 3O2(g) -->2Fe2O3(g) In a certain reaction, 27.3 g of iron is reacted with 79.9 g of oxygen How many grams of the excess reactant remain after the reaction is complete?

Respuesta :

McChuck
[tex]27.3gFe*( \frac{1molFe}{55.85gFe} )*( \frac{2molFe2O3}{4molFe} )*( \frac{159.7g Fe2O3}{1mol Fe2O3} ) = 39.03g Fe2O3[/tex]

[tex]79.9gO2*( \frac{1molO2}{32gO2} )*( \frac{2molFe2O3}{3molO2} )*( \frac{159.7g Fe2O3}{1molFe2O3} )= 265.83gFe2O3[/tex]

[tex]265.83gFe2O3-39.03g Fe2O3=226.8g Fe2O3[/tex]

[tex]226.8g Fe2O3 [/tex] is the answer.

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