the length is 18ft
and width is 16ft
we know that the perimeter of a rectangle is equal to
[tex](l + w) \times 2 [/tex]
which l and w stand for length and width.
so if we divide 68 by two, we will have the sum of the length and width.
[tex]68 \div 2 = 34[/tex]
so the sum of length and width is 34(68/2)
and sum of ratios is 17 (9+8)
[tex]34 \div 17 = 2[/tex]
so if we multiply the ratios by 2 we can find length and width
[tex]9 \times 2 = 18 \\ \\ \\ 8 \times 2 = 16[/tex]
good luck
