To solve this, you re-arrange the equation to get r by itself:
3r - 6 = 11q - 4
3r = 11q + 2 (add 6 to both sides to cancel out the -6)
r = [tex] \frac{11q}{3} + \frac{2}{3} [/tex] (divide both sides by 3 to get what r is)
This can also be written as: r = [tex]\frac{11q+2}{3} [/tex]
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ANSWER:
f(q) = [tex] \frac{11q}{3} + \frac{2}{3} [/tex]
OR
f(q) = [tex]\frac{11q+2}{3} [/tex]
OR
f(q) = (11q + 2) / 3 (if you can't put in fractions)
