A.) n ≥ − the quantity 4 times c minus 3 all over p
B.) n ≥ − the quantity 4 times c minus 13 all over p
C.) n ≤ − the quantity 4 times c minus 3 all over p
D.) n ≤ − the quantity 4 times c minus 13 all over p
The answer is the option A, which is: A.) n ≥ − the quantity 4 times c minus 3 all over p. The explanation is shown below: You have −np − 5 ≤ 4(c − 2) When you solve for n, you obtain: -np-5 ≤ 4(c-2) -np≤4c-8+5 Therefore, you have: n≤-(4c-3/p)
