The correct answer is
C) 1200 g/m3.
Let's see why. The relationship between liters and cube decimeters is
[tex]1 L = 1 dm^3[/tex]
Therefore,
[tex]1 g/L= 1 g/dm^3[/tex]
However, we also know that
[tex]1 dm^3 = 10^{-3} m^3[/tex]
Therefore,
[tex]1 L = 10^{-3} m^3[/tex]
and
[tex]1 \frac{g}{L}= 1 \frac{g}{10^{-3} m^3} =1 \cdot 10^3 \frac{g}{m^3} =1000 \frac{g}{m^3} [/tex]
Therefore, the density of the problem [tex]1.2 g/L[/tex] becomes
[tex]d=1.2 g/L=1200 g/m^3[/tex]
