A faucet is used to add water to a large bottle that already contained some water. after it has been filling for 4 ​seconds, the gauge on the bottle indicates that it contains 12 ounces of water. after it has been filling for 11 ​seconds, the gauge indicates the bottle contains 26 ounces of water. let y be the amount of water in the bottle x seconds after the faucet was turned on. write a linear equation that relates the amount of water in the​ bottle, y, to the time x.

Respuesta :

The problem gives us points (4, 12) and (11,26). We first find the slope using m=(y2-y1)/(x2-x1). We substitute and get m=(26-12)/(11-4). This simplifies to m = 2. We can then use the point-slope form y-y1 = m(x-x1). We substitute and get y - 12 = 2(x - 4). We distribute: y - 12 = 2x - 8. We add 12 to both sides to get our final answer, y = 2x + 4.

The linear equation that relates the amount of water in the​ bottle, y, to the time x is y=2x+4.

What is a linear equation?

A linear equation is an equation in which each term has at max one degree. Linear equations in variables x and y can be written in the form

y = mx + c.

Linear equation with two variables, when graphed on the cartesian plane with axes of those variables, give a straight line.

Given the water in the bottle after 4 seconds was 12 ounces, while the water in the bottle after 11 seconds is 26 ounces. Therefore, the rate of water filling in the bottle will be,

Rate = (26 - 12)ounces/(11 - 4)seconds = 14ounces/7 seconds = 2 ounces/second

Therefore, we can write the linear equation as,

y = 2x + c

Now to get the value of C, substitute the value of x as 4 while the value of y as 12. Therefore,

12 ounces = 2(4 seconds) + C

12 = 2(4) + c

12-8 = c

c = 4

Hence, the linear equation that relates the amount of water in the​ bottle, y, to the time x is y=2x+4.

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