Computer A can carry out analysis in 6 hours. That means in an hour, computer A does [tex] \frac{1}{6}[/tex] of the job.
Computer B can carry out analysis in 4 hours. That means in an hour, computer B does [tex] \frac{1}{4} [/tex] of the job.
If both computers work together, in an hour they do:
[tex] \dfrac{1}{6}+ \dfrac{1}{4} [/tex]
[tex]= \dfrac{2}{12}+ \dfrac{3}{12} \text{(equalize the denominators)} [/tex]
[tex]= \dfrac{5}{12} [/tex]
In an hour, they do [tex] \frac{5}{12}[/tex] of the job.
To finish the job, they need [tex] \frac{12}{5} [/tex] hours.
[tex] \dfrac{12}{5}[/tex] hours
= 2.4 hours
= 2 hours + 0.4 hour
= 2 hours + 0.4 × 60 minutes
= 2 hours 24 minutes
They finish analysing in 2 hours 24 minutes
