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A runner starts from rest and accelerates uniformly to a speed of 8.0 meters per second in 4.0 seconds. the magnitude of the acceleration of the runner is

Respuesta :

skyluke89
The magnitude of the acceleration of the runner is given by:
[tex]a= \frac{v_f-v_i}{t} [/tex]
where
[tex]v_f=8.0 m/s[/tex] is the final speed of the runner
[tex]v_i=0[/tex] is the initial speed of the runner
[tex]t=4.0 s[/tex] is the time taken

By substituting data into the equation, we find the magnitude of the acceleration:
[tex]a= \frac{8.0 m/s -0}{4.0 s}=2 m/s^2 [/tex]

The magnitude of the acceleration of the runner is [tex]\rm 2\;m/sec^2[/tex] .

Given :

Final Velocity = 8 m/sec

Initial Velocity = 0

Time = 4 sec

Solution :

We know that,

v = u + at  ---- (1)

Where,

v is final velocity,

u is initial velocity,

a is acceleration,

and t is time.

Now put the values of v, u and t in equation (1) we get,

[tex]\rm 8 = 0 +a\times 4[/tex]

[tex]\rm a = 2 \;m/sec^2[/tex]

The magnitude of the acceleration of the runner is [tex]\rm 2\;m/sec^2[/tex] .

For more information, refer the link given below

https://brainly.com/question/16710160?referrer=searchResults