a collection of nickels,dimes, and quarters totals $6.00. If there are 52 coins together and twice as many dimes as nickels, how many of each kind of coin are there?
For this case, the first thing we must do is define variables: x: number of nickels y: number of dimes z: number of quarters We now write the system of equations: [tex]0.05x + 0.10y + 0.25z = 6
x + y + z = 52
y = 2x[/tex] Solving the system of equations we have: [tex]x = 14
y = 28
z = 10[/tex] Answer: 14 nickels 28 dimes 10 quarters
