Respuesta :
To solve this problem you must apply the proccedure shown below:
1. You have to apply the following formula:
FV=PV[1+(i/n)]^4t
FV=3x1125
FV=3375
PV=1125
i=0.07
n=4
2. When you substitute the values into the formula, you obtain:
3375=1125[1+(0.07/4)]^4t
3. Now, you must solve for t, as following:
3375/1125=1+(0.07/4)^4t
3=(1.0175)^4t
log(3)=log(1.0175)^4t
log(3)=4t(log(1.0175))
4t=63.32
t=15.83 years
The answer is: 15.83 years.
1. You have to apply the following formula:
FV=PV[1+(i/n)]^4t
FV=3x1125
FV=3375
PV=1125
i=0.07
n=4
2. When you substitute the values into the formula, you obtain:
3375=1125[1+(0.07/4)]^4t
3. Now, you must solve for t, as following:
3375/1125=1+(0.07/4)^4t
3=(1.0175)^4t
log(3)=log(1.0175)^4t
log(3)=4t(log(1.0175))
4t=63.32
t=15.83 years
The answer is: 15.83 years.
Answer:
It takes 15.83 years to triple $1125 if it is invested at 7% interest.
Step-by-step explanation:
The future value (FV) of an investment of present value (PV) dollars earning interest at an annual rate of r compounded n times per year for a period of t years is:
[tex]FV=PV(1+\frac{r}{n})^{nt}[/tex]
where r/n is the interest per compounding period and nt is the number of compounding periods.
We solve for t,
[tex]PV\left(1+\frac{r}{n}\right)^{nt}=FV\\\\\frac{PV\left(1+\frac{r}{n}\right)^{nt}}{PV}=\frac{FV}{PV}\\\\\left(1+\frac{r}{n}\right)^{nt}=\frac{FV}{PV}\\\\\ln \left(\left(1+\frac{r}{n}\right)^{nt}\right)=\ln \left(\frac{FV}{PV}\right)\\\\nt\ln \left(1+\frac{r}{n}\right)=\ln \left(\frac{FV}{PV}\right)\\\\t=\frac{\ln \left(\frac{FV}{PV}\right)}{n\ln \left(1+\frac{r}{n}\right)}[/tex]
When [tex]FV = 3\cdot 1125=3375[/tex], PV = 1125, r = 7%, and n = 4, this becomes
[tex]t=\frac{\ln \left(\frac{3375}{1125}\right)}{4\ln \left(1+\frac{7/100}{4}\right)}\\\\t = \frac{\ln \left(3\right)}{4\ln \left(\frac{407}{400}\right)}\\\\t\approx15.83[/tex]
It takes 15.83 years to triple $1125 if it is invested at 7% interest.