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A tree casts a shadow 19 m. long. at the same time, the shadow cast by a 49-cm-tall statue is 98 cm. long. find the height of the tree. round results to the nearest unit.

Respuesta :

firuzer11
At the same time of the day the shadow's cast by objects due to sunlight are proportional (theoretically). So, here we apply proportionality to find the length of the tree.
[tex] \frac{length of the shadow}{height of the object causing the shadow} = \frac{length of the shadow}{height of the object causing the shadow}[/tex]
[tex]98 cm = 0.98 m[/tex] and [tex] 49 cm = 0.49 m [/tex]
[tex] \frac{19}{x} = \frac{0.98}{0.49} [/tex]
[tex]x = 9.5 m [/tex]

The height of the tree is 9.5 metres, after rounding it up we acquire the value 10 metres.

1rstar
Hey there !

As the timing is same , the length of shadows will be proportional ,

Let the height of tree be x ,

Hence ,
[tex] \dfrac{x}{19} = \dfrac{49}{98} \\ \\ x = 9.5 \: \: m[/tex]
Approximating to nearest value , height of tree is 10 m.

Hope it helps you :)

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