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A tiny sphere carrying a charge of 6.5 μc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere's potential energy

Respuesta :

skyluke89
The electric potential energy of the sphere is given by:
[tex]U=qV[/tex]
where
q is the charge of the sphere
V is the potential of the electric field where the sphere is located.

The sphere in this problem has a charge of
[tex]q=6.5 \mu C=6.5 \cdot 10^{-6} C[/tex]
while the potential is
[tex]V=240 V[/tex]
Therefore, the electric potential energy of the sphere is
[tex]U=qV=(6.5 \cdot 10^{-6} C)(240 V)=1.56 \cdot 10^{-3} J[/tex]

The potential energy of the sphere is calculated as [tex]1.6*10^-^3J[/tex]

Data;

  • Charge = 6.5μc
  • electric potential = 240V

Potential Energy

The potential energy of the sphere is calculated using the formula of potential energy and it's given as

[tex]E = qV[/tex]

  • q = charge
  • v = voltage

Let's substitute the values and solve the problem.

[tex]E = qV\\E = 6.5 * 10 ^-^6 * 240\\E = 1.6*10^-^3J[/tex]

The potential energy of the sphere is calculated as [tex]1.6*10^-^3J[/tex]

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