Respuesta :

bivekteaches
What you do is use equations of motions. Since the vehicle is decelerating so the acceleration is negative. 

Using the first equation of motion
v=u+a*t
u=47 (initial velocity)
a=-3  (final velocity)
v=0 (Complete stop)
therefore, 
→t=( v - u ) / a
   t= (0 - (-47) ) / (-3)
   t=15.67 second

Now,
Using second equation of motion,

→s=u*t +1/2*a*t²

    s=47 * (15.67) + 1/2 * (-3) * (15.67²)
    s=736.49 -368.32

Answer= 368.16 feet
raphealnwobi

It takes the car 368.2 feet before coming to a complete stop.

Using newton's law:

v² = u² + 2as

Where u is the initial velocity, v is the final velocity, a is the acceleration and s is the distance.

Given that:

u = 47 ft/sec, v = 0(stop), a = -3 ft/sec². Hence:

v² = u² + 2as

0² = 47² + 2(-3)s

6s = 2209

s = 368.2 feet

Hence it takes the car 368.2 feet before coming to a complete stop.

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