Answer:
The magnitude and direction of the resultant displacement is 5 km and 16.26° North -east.
Explanation:
Given that,
Distance in north = 1.4 km
Distance in east = 4.8 km
We need to calculate the magnitude of resultant displacement
Using formula of displacement
[tex](AC)^2=AB^2+BC^2[/tex]
[tex]AC=\sqrt{(AB)^2+(BC)^2}[/tex]
[tex]AC=\sqrt{(1.4)^2+(4.8)^2}[/tex]
[tex]AC=5\ km[/tex]
We need to calculate the direction
Using formula of direction
[tex]\tan\theta=\dfrac{y}{x}[/tex]
[tex]\tan\theta=\dfrac{1.4}{4.8}[/tex]
[tex]\theta=\tan^{-1}0.29167[/tex]
[tex]\theta=16.26^{\circ}\ N-E[/tex]
Hence, The magnitude and direction of the resultant displacement is 5 km and 16.26° North -east.
