Respuesta :

altavistard
Trick question!  Note that (anything)^0 = 1.  So, certainly, (-5a^5b^4c^3)^0 = 1.
[tex]\bf \left( \cfrac{cheeseburger}{spaghetti} \right)^0=ducks^0=bologne^0=(15\cdot 25+3\cdot 100000)^0=1[/tex]


anything whatsoever, with the sole exception of 0 itself, raised at the 0 power, is 1.

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