y-intercept is formed when the coordinate x of the graph equals 0.
we need to substitute 0 to the x of all options, and see if the value of f(x) equals 5
option 1
f(x) = 7(b)⁰ - 2
f(x) = 7(1) - 2
f(x) = 7 - 2
f(x) = 5
option 2
f(x) = -3(b)⁰ - 5
f(x) = -3(1) - 5
f(x) = -3 - 5
f(x) = -8
option 3
f(x) = 5(b)⁰ - 1
f(x) = 5(1) - 1
f(x) = 5 - 1
f(x) = 4
option 4
f(x) = -5(b)⁰ + 10
f(x) = -5(1) + 10
f(x) = -5 + 10
f(x) = 5
option 5
f(x) = 2(b)⁰ + 5
f(x) = 2(1) + 5
f(x) = 2 + 5
f(x) = 7
The correct answer is option 1 and option 4. When the coordinate x equals 0, they have coordinate y equals 5, that makes y-intercept on (0,5)
