joshuaswag3319 joshuaswag3319
  • 10-06-2018
  • Mathematics
contestada

Find the center and the radius of the circle defined by the equation x^2-8x+y+12y+36=0

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caylus
caylus caylus
  • 15-06-2018
Hello,
center is (4,-6)
radius=4
since
[tex]x^2-8x+y^2+12y+36=0\\ x^2-2*4x+16-16+y^2+2*6y+36=0\\ (x-4)^2+(y+6)^2=4^2 [/tex]


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