Respuesta :

gmany
[tex]\dfrac{2x-3}{x}:\dfrac{7}{x^2}=\dfrac{2x-3}{x}\cdot\dfrac{x^2}{7}=\dfrac{2x-3}{1}\cdot\dfrac{x}{7}\\\\=\dfrac{(2x-3)\cdot x}{1\cdot7}=\dfrac{2x^2-3x}{7}[/tex]

Answer:

2x-3/7x

Step-by-step explanation: