Respuesta :

[tex]\bf -6x-10\ \textgreater \ 14+2x \\\\\\ \underline{(-2x+10)-6x-10\ \textgreater \ 14+2x+(-2x+10)} \\\\\\ -8x\ \textgreater \ 24\implies x\ \textgreater \ \cfrac{24}{-8}\implies x\ \textgreater \ -3[/tex]