katyabitzesp6zp82 katyabitzesp6zp82
  • 10-06-2018
  • Mathematics
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Which rectangular equation is equivalent to the polar equation r csc theta=8?

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gian09ortegap93ofg gian09ortegap93ofg
  • 10-06-2018
x=rcos(t), y=rsin(t). so y/sin(t) = r => csc(t) = r/y. so for now we have r*(r/y)=8. To solve for r, do x^2 + y^2 = r^2, so r=sqrt(x^2 + y^2). So we have sqrt(x^2 + y^2)*(sqrt(x^2 + y^2)/y)=8, or (x^2+y^2)/y = 8, or x^2/y + y = 8.
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brendaad32
brendaad32 brendaad32
  • 21-09-2018

X^2+(Y-4)^2=16

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