Respuesta :

AL2006
Acceleration = (change in speed) / (time for the change)

Acceleration = (8.0 m/s) / (4 sec)

Acceleration = (8/4) (m/s /s)

Acceleration =  2 m/s²

The acceleration of Joe as he ran at constant acceleration is 2m/s².

Given the data in the question;

Since Joe starts from rest,

  • Initial velocity; [tex]u = 0[/tex]
  • Final velocity; [tex]v = 8m/s[/tex]
  • Time taken; [tex]t = 4s[/tex]

Acceleration; [tex]a =\ ?[/tex]

To determine the acceleration, we use the First Equation of Motion:

[tex]v = u + at[/tex]

Where v is final velocity, u is initial velocity, a is acceleration and t is time taken.

We substitute our given values into the equation

[tex]8m/s = 0 + [ a * 4s]\\\\8m/s = a * 4s\\\\a = \frac{8m/s}{4s} \\\\a = 2m/s^2[/tex]

Therefore, the acceleration of Joe as he ran at constant acceleration is 2m/s².

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