contestada

For Hardy-Weinberg equilibrium to occur (that is, for evolution not to occur), several conditions that would cause evolution must be absent. Which of the following conditions are required for Hardy-Weinberg equilibrium? Check all that apply. mutations occur mating is random the population is large there is no migration into or out of the population the population must relocate to another place or region

Respuesta :

the answer that you're looking for is B,C, and D.

hope this helped please rate and like so more people will see the answer.

For Hardy-Weinberg equilibrium to occur, there should be random mating, large population size and no migration into or out of the population.

What do you mean by Hardy-Weinberg equilibrium?

  • "It states that in the absence of some factors the genetic variation in a population remains constant from one generation to another."
  • It follows the equation: [tex](p+q)^{2}[/tex]=1 which is equal to [tex]p^{2} +2pq + q^{2}[/tex] =1

Where, [tex]p^{2}[/tex]= dominant homozygous frequency, [tex]q^{2}[/tex]= recessive homozygous frequency and [tex]2pq[/tex]= heterozygous frequency.

  • Conditions for Hardy-Weinberg equilibrium include: random mating,  no mutation (as mating will result in genetic variation), infinite population size, no gene flow ( no migration into and out of the population).

Hence, the correct options include: mating is random, the population is large and there is no migration into or out of the population.

To know more about Hardy-Weinberg equilibrium here

https://brainly.com/question/14669053

#SPJ2

Otras preguntas