A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recessive allele (h). Use the Hardy-Weinberg equation to determine the frequencies of the three genotypes: f(HH) = p2 = f(Hh) = 2pq = f(hh) = q2 =
the frequencies of the genotypes are as follows: p2= 0.04 ie, frequency of HH =4% 2pq= 0.32 ie, frequency of Hh= 32% q2= 0.64 ie, frequency of hh = 64%
