the moles of Na3PO4 produced from 3.24 moles of ammonia NaCl is

Answer : B). - 1.08 mol
Explanation :
I think question should be "The moles of Na₃PO₄ produced from 3.24 moles of NaCl is"
The balanced reaction is given as
(NH₄)₃PO₄ + 3NaCl → 3NH₄Cl + Na₃PO₄
The stoichiometric ratio between NaCl and Na₃PO₄ is 3 : 1.
Hence,
produced Na₃PO₄ moles = reacted NaCl moles / 3
= 3.24 mol / 3
= 1.08 mol