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Solve this Stoichiometry problem

Solve the following problem showing all of your work and including all units. You can solve the problem in several steps or as a tandem conversion problem.

How many grams of Br2 are needed to completely convert 15.0 g Al to AlBr3 ?

Al (s) + Br2 (l) --> AlBr3 (hint: the equation is not balanced)

Respuesta :

PBCHEM

Answer : The balanced equation is;


2Al + 3 [tex]Br_{2}[/tex] ----> 2Al[tex]Br_{3}[/tex].


So now, to calculate how many grams of [tex]Br_{2}[/tex] will be needed to completely convert 15 g of Al[tex]Br_{3}[/tex],


In the reaction 2 moles of Al and 3 moles of [tex]Br_{2}[/tex] will be needed to produce 2 moles of Al[tex]Br_{3}[/tex].


So, (15.0 g Al) X (1 mole Al / 26.98 g Al) X (3 moles [tex]Br_{2}[/tex] / 2 moles Al) X (159.81 g [tex]Br_{2}[/tex] / 1 mole [tex]Br_{2}[/tex])

= 133 g [tex]Br_{2}[/tex]


Hence, 133g of [tex]Br_{2}[/tex] will be needed to completely convert 15 g of Al into Al[tex]Br_{3}[/tex].


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