contestada

A water main for a street is being laid using mechanical joint pipe. the pipe comes in 18-foot and 20-foot sections, and a designer determines that the water main would require 14 fewer sections of 20-foot pipe than if 18-foot sections were used. find the total length of the water main.

Respuesta :

calculista

Let

x--------> the total length of the water main


we know that

the number of 20 ft pipes is x/20

and

the number of 18 ft pipes is x/18

Since they differ by 14 pipes,

we have the equation

x/18 - x/20 = 14

Solve for x (by canceling fractions)

20x - 18x = 14*18*20

x = (14*18*20)/2

x = 2,520 ft


therefore


the answer is

the total length of the water main is 2,520 ft

carlosego

To solve this problem you must apply the proccedure shown below:

1. You can write the following expression, where the variable [tex] x [/tex] is the total length of the water main:

[tex] \frac{x}{18}-\frac{x}{20}=14 [/tex]

2. Now, solve for [tex] x [/tex], as following:

[tex] \frac{10x-9x}{180}=14\\ x=(14)(180)\\ x=2520 [/tex]

Therefore, the answer is: [tex] 2520 feet [/tex]

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