To calculate the concentration of H3O+
1- when PH = 2.5 :
The explanation:
we are going to use this formula:
PH = - ㏒[H3O+]
and we here have PH = 2.5 so, by substitution:
2.5 = -㏒ [H3O+]
∴ [H3O+] = 0.00316 ≈ 0.003
2- when PH = 2.51 :
The explanation:
we are going to use this formula:
PH = - ㏒[H3O+]
when here we have PH = 2.51 so, by substitution:
2.51 = - ㏒[H3O+]
∴[H3O+] = 0.00309 ≈ 0.003
3- when PH = 2.52 :
The explanation:
we are going to use this formula:
PH = - ㏒[H3O+]
when here we have PH =2.52 so, by substitution:
2.52 = -㏒[H3O+]
∴[H3O+] = 0.00301 ≈ 0.003
we can see that when the the number of digits to the right of the decimal place in ph increase, the number of significant figures in concentration decrease.
