contestada

Which of the following shows both the boundary lines to the solution of the inequality lx+3l-2[tex] \leq [/tex] 0, and a value that is included in the region which determines the solution?

x = 0

x = –1

x = 2

x = 5

Respuesta :

sarkhan2018

Solving this inequality will yield the answer


[tex] |x+3|\leq 2 [/tex]

[tex] \left \{ {{x+3 \leq 2} \atop {x+3 \geq -2}} \right. [/tex]

[tex] \left \{ {{x \leq -1} \atop {x \geq -5}} \right. [/tex]

-1 is located on the border and it is the correct answer from these below given multiple choices. 


JeanaShupp

Answer: x = –1

Step-by-step explanation:

Given inequality: [tex]|x+3|-2 \leq0[/tex]

When we simplify the above inequality we get,

[tex]|x+3|\leq2\\\\\Rightarrow-2\leq(x+3)\leq2\\\\\Rightarrow-2-3\leq x\leq2-3\\\\\Rightarrow-5\leq x\leq -1[/tex]

From all the given options only -1 t is included in the region [-1,-5].

Hence, x = –1 is the value that is included in the region which determines the solution.

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