Answer: 4.50 g.
Explanation:
1) Chemical reaction
antimony(III) sulfide + hydrochloric acid → antimony(III) chloride and hydrogen sulfide gas.
Sb₂S₃ + HCl → SbCl₃ + H₂S
2) Balanced chemical equation
Sb₂S₃ + 6HCl → 2SbCl₃ +3H₂S
3) Mole ratio
1 mol Sb₂S₃ : 2SbCl₃
4) Convert 3.35 g sample of stibnite ton number of moles
Molar mass Sb₂S₃ = 339.715 g/mol
number of moles = mass in grams / molar mass = 3.35 g / 339.715 g/mol = 0.00986 mol
5) Proportion
1 mol Sb₂S₃ / 2 mol SbCl₃ = 0.00986 mol Sb₂S₃ / x
x = 0.01972 mol SbCl₃
6) Convert 0.01972 mol SbCl₃ to grams
molar mass SbCl₃ = 228.13 g/mol
mass in grams = molar mass × number of moles = 228.13 g/mol × 0.01972 mol = 4.50 g.
