Your expression looks like this: [tex] \frac{3}{4}(5z+16) [/tex]. The mathematical operation indicated by that is multiplication. We will distribute the 3/4 into the 5z by multiplication. If it's easier, think of the problem like this: [tex] \frac{3}{4}( \frac{5z}{1}+ \frac{16}{1}) [/tex]. When you multiply fractions you don't need a common denominator. You just multiply straight across the top and straight across the bottom. 3 times 5z is 15, and 4 times 1 is 4 so that comes to [tex] \frac{15}{4}z [/tex]. And 3 times 16 is 48, and 4 times 1 is 4, and 48/4 is 12. So the final simplified expression is [tex] \frac{15}{4}z+12 [/tex]. Your answer is B.
