Write an equation of the line that passes through 9, 6 and is perpendicular to the line whose equation is y equals -1 over 3 x + 7

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06-07-2018
Mathematics

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Write an equation of the line that passes through 9, 6 and is perpendicular to the line whose equation is y equals -1 over 3 x + 7

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Luv2Teach Luv2Teach · Answer 1 · 2018-07-06T16:57:40+02:00

If the line that goes through (9, 6) is perpendicular to y = -1/3x + 7, then their slopes will be opposite reciprocals. The slope of the line given is -1/3. The opposite reciprocal of -1/3 is +3. If we have our new line passing through point with x coordinate 9 and y coordinate 6, we will use that x and y and the slope of 3 to solve the slope-intercept equation for b. Like this: 9 = 3(6) + b. 9 = 18 + b and b = -9. That means that the new equation, the one that is perpendicular to the given line, is y = 3x - 9.

jayden4210 jayden4210 · Answer 2 · 2020-11-02T15:33:13+01:00

Answer:

Step-by-step explanation:If the line that goes through (9, 6) is perpendicular to y = -1/3x + 7, then their slopes will be opposite reciprocals. The slope of the line given is -1/3. The opposite reciprocal of -1/3 is +3. If we have our new line passing through point with x coordinate 9 and y coordinate 6, we will use that x and y and the slope of 3 to solve the slope-intercept equation for b. Like this: 9 = 3(6) + b. 9 = 18 + b and b = -9. That means that the new equation, the one that is perpendicular to the given line, is y = 3x - 9.