The nth term is (presuming the denominator on the first is a typo)
[tex]-\dfrac{n}{(-3)^n}[/tex]
The ratio of successive terms is
[tex]\dfrac{ \frac{n+1}{(-3)^(n+1)}}{\frac{n}{(-3)^n}} = \frac{n+1}{-3n}[/tex]
The limit is -1/3, absolute value less than 1, so the series converges. It has a sum -- that's what converges means.