Respuesta :
[tex]f(x)=5x+12\\\\
y=5x+12\\
5x=y-12\\
x=\dfrac{y-12}{5}\\\\
f^{-1}(x)=\dfrac{x-12}{5}[/tex]
For this case we have the following function:
[tex]f (x) = 5x + 12 [/tex]
Rewriting the function we have:
[tex]y = 5x + 12 [/tex]
From here, we clear the value of x.
We have then:
[tex]5x = y-12[/tex]
[tex]x = \frac{y-12}{5} [/tex]
Then, we return the change of variables.
We have then:
[tex]y = \frac{x-12}{5} [/tex]
Rewriting, we have that the inverse function is:
[tex]f(x)^{-1}=\frac{x-12}{5}[/tex]
Answer:
D.x-12/5
[tex]f (x) = 5x + 12 [/tex]
Rewriting the function we have:
[tex]y = 5x + 12 [/tex]
From here, we clear the value of x.
We have then:
[tex]5x = y-12[/tex]
[tex]x = \frac{y-12}{5} [/tex]
Then, we return the change of variables.
We have then:
[tex]y = \frac{x-12}{5} [/tex]
Rewriting, we have that the inverse function is:
[tex]f(x)^{-1}=\frac{x-12}{5}[/tex]
Answer:
D.x-12/5