Respuesta :

x^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2

We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2

where
(h,k) = (0,0) is the center
r = 4 is the radius

The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4. 

Answer: r = 4
lhmarianateixeira

Convert the cartesian equation [tex]x^2 +y^2=16[/tex] to a polar equation will have that  [tex](x-0)^2+(y-0)^2 = 4^2[/tex].

How does polar coordinate work?

Polar coordinates are a way of expressing position in a two-dimensional plane. Cartesian coordinates, also called rectangular coordinates, use a distance in each of the two dimensions to locate a point, but polar coordinates use an angle and a distance.

Given that:

[tex]x^2+y^2 = 16[/tex]

Is written as:

[tex](x-0)^2+(y-0)^2 = 4^2[/tex]

The second equation is in the form is:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

where,

  • (h,k) = (0,0) is the center
  • r = 4 is the radius

That results in:

[tex](x)^2 + (y)^2 = (4)^2[/tex]

See more about polar coordinate at brainly.com/question/26026667?