Is there a series of rigid transformations that could map ΔQRS to ΔABC? If so, which transformations could be used?

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kennyxue54pbf7zy kennyxue54pbf7zy · Answer 1 · 2018-07-07T00:24:47+02:00

ΔQRS can be translated so that Q is mapped to A and then reflected across the line containing QS is the correct answer.

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JeanaShupp JeanaShupp · Answer 2 · 2019-06-26T06:48:44+02:00

Answer: Yes, ΔQRS can be translate to so that Q is mapped to point A, then reflect across line containing QS.

Step-by-step explanation:

In the given picture , we have two triangles ΔQRS and ΔABC in which we have ,

QR=AB = 16 cm

RS=BC= 24 cm

∠R=∠B=90°

By SAS postulate of congruence , ΔQRS ≅ ΔABC.

There are three main rigid transformations which produces congruent images.

1) Translations 2) Rotation 3) Reflection

When we look the given picture, it can be seen that ΔABC is the mirror image of ΔQRS.

But line QS is at some distance from AC , so we first translate ΔQRS to so that Q is mapped to point A, then reflect across line containing QS.