In the diagram below, jkjk is an equilateral triangle and Km jl

The correct option is option D: ΔJKM is 30-60-90 triangle.
The triangle whose all the three sides are equal is called equilateral triangle.
Three angles of an equilateral triangle is also equal which is 60°.
In ΔJKL, KM is perpendicular to JL i.e. KM⊥JL
∠KMJ=∠KML=90°
Between ΔJKM and ΔKLM
KJ=KL (As equilateral triangles ΔJKL has all sides equal)
∠KJM=∠KLM (=60°)
∠KMJ=∠KML=90°
ΔJKM ≅ ΔKLM (Angle-Angle-side)
ΔJKM and ΔKLM are congruent.
⇒∠JKM=∠LKM
As ∠JKL=60° (ΔJKL is an equilateral triangle.)
Then, ∠JKL=∠JKM+∠LKM
Let ∠JKM=∠LKM=x
⇒60°=x+x
⇒2x=60°
⇒x=30°
⇒∠JKM=∠LKM=30°
Therefore in ΔJKM,
∠JKM=30°
∠KJM=60°
∠KMJ=90°
Threfore, ΔJKM is 30-60-90 triangle.
Checking all options,
A. ΔJKM is 45-45-90 triangles. This is incorrect because ∠KJM =60°
B. KM=2JM This option is incorrect as tan60°=√3=KM/JM⇒KM=√3JM
C. JM=KM This option is incorrect as tan60°=√3=KM/JM⇒KM=√3JM
D. ΔJKM is 30-60-90 triangle. This option is correct as in ΔJKM, ∠JKM=30°, ∠KJM=60°, ∠KMJ=90°
Therefore, The correct option is option D: ΔJKM is 30-60-90 triangle.
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