Fair view high school has and anime( Japanese animation ) that any student can attend. The relative frequency table shows the proportion of students in the high school who take Japanese and or are in the anime club.
0.15 take Japanese and are in the anime club . 0.05 take Japanese but are not in the club. 0.01 don't take Japanese and are in the club. 0.79 don't take Japanese and aren't in the club. A total of 0.16 are in the club and take Japanese, the total of people not in anime club is 0.84 .

Given that a student takes Japanese what is the likelihood that he or she in is the anime club?

A: about 94%
B: 20%
C: 15%
D: 75%

In probability theory, conditional probability is a measure of the likelihood of an event occurring if another event has already occurred. Assume that A and B are two events. Given that B has already occurred. Then the conditional probability [P(A|B)] can be calculated as

P(A|B) = P(A ∩ B)/P(B), where A ∩ B denotes the event that A and B both occur together.

How to solve this problem?

Let C denotes the event "a student takes Japanese" and D denotes the event "he or she is in is the anime club". Clearly, we have to find the probability of D knowing the fact that C has already occurred.

Here, P(C) = number of students take Japanese = 0.20

P(D ∩ C) = number of students take Japanese and are in anime club = 0.15

Then, P(D|C) = P(D ∩ C)/P(C) = 0.15/0.20 = 0.75

So, the percentage is 0.75 × 100% = 75%

Therefore, If a student takes Japanese, there is a 75% chance that he or she will join the anime club.

Learn more about the conditional probability -

https://brainly.com/question/17075372

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