Write an equation for a parabola in which the set of all points in the plane are equidistant from the focus and line. F(–2, 0); x = 2

Respuesta :

DeanR
The line is called the directrix.  Here we have a vertical directrix, so a parabola sideways from usual.

Geometry is best done with squared distances.  The squared distance from an arbitrary point (x,y) to the vertical line x=2 is [tex](x-2)^2.[/tex]

We equate that to the squared distance of (x,y) to the focus (-2,0): 

[tex](x-2)^2 = (x - -2)^2 + (y - 0)^2[/tex]

[tex]x^2 -4x + 4=x^2 +4x +4 + y^2[/tex]

[tex]-8x = y^2[/tex]

We could call that done.  A more standard form might be

[tex]x =- \dfrac 1 8 \ y^2[/tex]

Answer:

x = [tex]-\frac{1}{8}[/tex][tex]y^{2}[/tex]

Step-by-step explanation:

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