By definition, the generic equation of the line is given by:
[tex] y-yo = m (x-xo)
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Where,
(xo, yo): ordered pair where the line passes
m: slope of the line
For this case we have:
[tex] (xo, yo) = (1, 1)
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Suppose that m is the value of the slope.
Substituting values we have:
[tex] y-1 = m (x-1)
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Rewriting the equation in its standard form we have:
[tex] y = mx + (1-m)
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Answer:
the standard form of the line that is:
[tex] y = mx + (1-m)
[/tex]
Note: Substituting the value of the slope, you have the final answer.
