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a bird of species a when diving can travel four times as fast as a bird of species b top speed if the total speeds of these two birds is 180 miles per hour find the fastest speed of the bird species a and the fastest speed of species B

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BiologiaMagister
x will be the speed of species b and 4x will be the speed of species a:

x + 4x = 180
5x = 180
x = 180 / 5
x = 36 m/h

If species b has a speed of 36 m/h, the speed of species a is 4 times that:

4 x 36 = 144 m/h.


Answer:

[tex]\boxed {\bf A~=~36~m/h~and~B~=~144~m/h}[/tex]


Hope it helped,

Happy homework/ study/ exam!

An equation is formed of two equal expressions. The speed of dive of species A is 144 miles per hour, while the top speed of species B is 36 miles per hour.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given the bird of species A when diving can travel four times as fast as the bird of species B's top speed. Therefore, we can write,

A = 4B

Also, it is mentioned that the sum of their speeds is 180 miles per hour. Therefore,

A + B = 180

4B + B = 180

5B = 180

B = 36 miles per hour

A = 4B = 4(36) = 144 miles per hour

Hence, the speed of dive of species A is 144 miles per hour, while the top speed of species B is 36 miles per hour.

Learn more about Equation:

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